【Python】计算ABCD宝物合成，及所需忍币

如题，昨天合三勾刀鞘的时候，估算自己的库存宝物还可以合成多少个A宝。已知 1S = 5A；1A = 4B；1B = 3C；1C = 3D。

于是写了这段代码，可以估算一下买图纸合宝物所需的忍币数喔，欢迎自取

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A = 8

B = 115

C = 113

D = 309

print("now you have "+str(A)+" A, "+str(B) + " B, " + str(C) + " C, " + str(D) + " D")

cost = 0

C = D // 3 + C

cost = cost + D//3 * 500

print(str(D) + " D -> " + str(D//3) + " C" + ", cost = " + str(D//3*500))

B = C // 3 + B

cost = cost + C//3 * 2000

print(str(C) + " C -> " + str(C//3) + " B" + ", cost = " + str(C//3*2000))

A = B // 4 + A

cost = cost + B//4 * 6000

print(str(B) + " B -> " + str(B//4) + " A" + ", cost = " + str(B//4*6000))

print("now you have " + str(A) + " A" + ", total cost = " + str(cost))

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运行示例，比如我仓库里有8A，115B，113C， 309D

没有py环境的朋友可以百度一些在线python运行环境嗷

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如有错误，请多指正